The upper part of a tree broken at a certain height makes

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The upper part of a tree broken at a certain height makes an angle of 60° with the ground at a distance of 10 metre from its foot. The original height of the tree was

AB = Height of tree
Let the tree break at point C.
BC = x metre
∴ AC = CD
∠CDB = 60°; BD = 10 metre
In ∆BCD,

tan 60° =		BC	⇒ √3 =	x
		BD		10

⇒ x = 10 √3 metre

Again, sin 60° =	BC
	CD

⇒		√3	=	10√3
		2		CD

⇒ CD =	2 × 10√3	= 20 metre
	√3

∴ Height of tree = AB
= (20 + 10√3) metre
= 10 (2 + √3) metre