-
15 liters of a mixture contains 20 % alcohol and the rest water. If 3 liters of water be mixed in it, the % of alcohol in the new mixture will be —
-
- 17
-
16 2 3 -
18 1 2 - 15
Correct Option: B
On the basis of given question , we can say that
In the mixture, water is added
Hence, % of water in the mixture = 100 – 20 = 80%
Now applying the given rule, we have
| The percentage of water in the new mixture = 15 |  |  | = 3 | 100 – z |
| ∴ z = | % | 6 |
| Required answer i.e. % of alcohol in the new mixture = 100 – | = | 6 | 6 |
| Required answer = | = 16 | % | 3 | 3 |
