Alligation or Mixture
- A merchant has 50 kg. of sugar part of which he sells at 8 % profit and the rest at 18 % profit. He gains 14 % on the whole. The quantity sold at 18 % profit is —
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Here , C1 = 8% , C2 = 18% and Mean Profit ( M ) = 14%
Ratio of 1st and 2nd part = 4 : 6 = 2 : 3
Using the method of alligation ,
Correct Option: B
Here , C1 = 8% , C2 = 18% and Mean Profit ( M ) = 14%
Ratio of 1st and 2nd part = 4 : 6 = 2 : 3Quantity sold at 18% = 50 × 3 = 30 kg 2
Using the method of alligation ,
- Two vessels A and B contains milk and water mixed in the ratio 5 : 3 and 2 : 3. When these mixtures are mixed to form a new mixture containing half milk and half water, they must be taken in the ratio —
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As per the given question , we can say that
Milk in A = 5 of whole, Milk in B = 2 of whole, 8 5 Milk in mixture of A and B = 1 2
∵ By alligation rule ,Correct Option: C
As per the given question , we can say that
Milk in A = 5 of whole, Milk in B = 2 of whole, 8 5 Milk in mixture of A and B = 1 2
∵ By alligation rule ,(Mix. in A) : (Mix. in B) = 1 : 1 10 8
(Mix. in A) : (Mix. in B) = 4 : 5
- The ratio of milk and water in 66 kg of adulterated milk is 5 : 1. Water is added to it to make the ratio 5 : 3. The quantity of water added is —
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Here , Ratio of of milk and water in 66 kg of adulterated milk = 5 : 1
In first mixture :Milk = 66 × 5 = 55 kg 6
and water = 11 kg
In second mixture :
Ratio = 5 : 3If milk is 55 kg then water = 3 × 55 5
Correct Option: A
Here , Ratio of of milk and water in 66 kg of adulterated milk = 5 : 1
In first mixture :Milk = 66 × 5 = 55 kg 6
and water = 11 kg
In second mixture :
Ratio = 5 : 3
New quantity of water = 33 kgIf milk is 55 kg then water = 3 × 55 5
∴ Water to be added = 33 - 11 = 22 kg.
- In what proportion must wheat at Rs. 1·60 per kg be mixed with wheat at Rs. 1·45 per kg. So that the mixture be worth Rs. 1·54 per kg?
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Here , C1 = 160 paise , C2 = 145 paise and Mean cost Price ( M ) = 154 paise
Required ratio = ( M - C2 ) : ( C1 - M )
Correct Option: B
Using the Alligation method ,
Here , C1 = 160 paise , C2 = 145 paise and Mean cost Price ( M ) = 154 paise
Required ratio = ( M - C2 ) : ( C1 - M )
∴ (Dearer wheat) : (Cheaper wheat) = 9 : 6
Hence , (Dearer wheat) : (Cheaper wheat) = 3 : 2
- In what proportion should water and wine at Rs. 22·50 a liter be mixed to reduce the price to Rs. 18 a liter ?
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Here ,Mean cost price Z = Rs.18
According to question , we haveRequired proportion = C2 – Z Z – C1 Required proportion = 20·50 – 18 18 – 0 Correct Option: A
Here ,Mean cost price Z = Rs.18
According to question , we haveRequired proportion = C2 – Z Z – C1 Required proportion = 20·50 – 18 18 – 0
[Water worths Rs. 0 a litre]Required proportion = 4·50 = 1 : 4. 18