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The angle of elevation of the top of a tower from a point 20 m away from its base is 45°. The height of the tower is :
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- 10 m
- 20 m
- 40 m
- 20 √3 m
Correct Option: B
From the given figure , we can see that
Let us assume the angle of elevation ∠MŌP = 45°. and The height of the tower = h
Given :- MO = 20 m
In triangle MOP ,
| tan45° = | PM | MO |
| ⇒ | h | = | tan45° | = 1 |
| 20 |
∴ h = 20 m
