-
A tower stands on a horizontal plane. A man on the ground 100 m from the base of the tower finds the angle of elevation of the top of the tower to be 30°. What is the height of the tower?
-
- 100 m
- 100 √3
- 100/ √3
- None of these
Correct Option: C
Let us draw the figure from the given question.
Given :- θ = 30° , AB = h and AC = 100 m
| In triangle ACB , tanθ = | AB |
| AC |
| tan 30° | = | h | 100 |
| ⇒ | 1 | = | h | |
| √3 | 100 |
| ⇒ | h | = | 100 | m. | √3 |
| Hence , the height of the tower is | 100 |
| √3 |
