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In a quadrilateral ABCD, ∠B = 90° and AD2 = AB2 + BC2 + CD2, then ∠ACD is equal to:
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- 90°
- 60°
- 30°
- 20°
- None of these
Correct Option: A
In a quadrilateral ABCD,
Given :- ∠B = 90°
AB2 + BC2 + CD2 = AC2 + CD2 = AD2 { ∴ In triangle ABC , AB2 + BC2 = AC2 }
So, in triangle ACD, angle opposite to AD = 90° ( by Converse of Pythagoras theorem)
⇒ ∠ACD = 90°
