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In the given figure, side BC of Δ ABC is produced to form ray BD and CE || BA. Then ∠ ACD is equal to :
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- ∠A - ∠B
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1 (∠A + ∠B) 2 - ∠A + ∠B
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1 (∠A - ∠B) 2 - None of these
Correct Option: C
From above given figure , we can see that
CE || BA and AC is the transversal.
∴ ∠4 = ∠1 (alternate interior ∠s) .......... ( 1 )
Again, CE || BA and BD is the transversal.
∴ ∠5 = ∠2 (corresponding ∠s) ................( 2 )
Adding equations ( 1 ) and ( 2 )
∴ ∠4 + ∠5 = ∠1 + ∠2
∴∠ACD = ∠A + ∠B.
