Through O, draw a line l parallel to both AB and CD. Then ∠1 = 45° (alt. ∠S) and ∠2 = 30° (alt. ∠S) ∴ ∠BOC = ∠1 + ∠2 = 45° + 30° = 75° So, X = 360° – ∠BOC = 360° – 75° = 285° Hence X = 285°.
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