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A spherical ball of lead, 3 cm in diameter is melted and recast into three spherical balls, The diameter of two of these are 1.5 cm and 2 cm respectively. The diameter of the third ball is ?
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- 2.66 cm
- 2.25 cm
- 3 cm
- 3.5 cm
Correct Option: B
∵ 4/3πr3 = 4/3π x [(3/2)3 - {(3/4)3 + 13 } ]
⇒ r3 = 125/64 = (5/4)3
⇒ r = 5/4
∴ Diameter = (5/4) x 2 cm = 2.5 cm.
