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The base radius and height of a cone are doubled. The ratio of the new volume to original volume is ?
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- 8 : 7
- 8 : 3
- 8 : 1
- 8 : 5
Correct Option: C
Let original radius = r and height = h
Original volume = (1/3)πr2h
New radius = 2r and new height = 2h
∴ New volume = 1/3 x π(2r)2 x 2h = 8/3πr2h
Required ratio = 8/3πr2h : 1/3πr2h = 8 : 1