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A right circular cone of height h is cut by a plane parallel to the base at a distance h/3 from the base, then the volumes of the resulting come and the frustum are in the ratio ?
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- 4/7
- 8/19
- 6/19
- 18/19
Correct Option: B
The volume of the original cone is V = (πR2h)/3
The height and the radius of the smaller cone are 2h/3 and 2R/3, respectively
⇒ 1/3π (2R/3)2 x 2h/3 = 8V/27
∴ Volume of the frustum = (V - 8V/27) = 19V/27
So, the required ratio is 8 : 19 .
