Unitary Method
- 20 men can build 56 m long wall in 6 days. What length of a similar wall can be built by 70 men in 3 days ?
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Let the required length be L m.
More men, More length (Direct proportion)
Less days, Less length (Direct proportion)
Men 20 : 70
Days 6 : 3
∴ (20 x 6 x L) = (70 x 3 x 56)Correct Option: B
Let the required length be L m.
More men, More length (Direct proportion)
Less days, Less length (Direct proportion)
Men 20 : 70
Days 6 : 3
∴ (20 x 6 x L) = (70 x 3 x 56)
∴ L = (70 x 3 x 56) / (20 x 6) = 98 m
- Shantanu completes 5/8 of a job in 20 days. At this rate, how many more days will he take to finish the job ?
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Let the required number of days be N.
Remaining work = 1 - 5/8 = 3/8
Less work, Less days (Direct proportion)
5/8 : 3/8 : : 20 : NCorrect Option: D
Let the required number of days be N.
Remaining work = 1 - 5/8 = 3/8
Less work, Less days (Direct proportion)
5/8 : 3/8 : : 20 : N
⇒ N = (3/8) x 20 x 8/5
∴ N = 12 days
- Maganlal, a worker, makes an article in every 2/3h. If he works for 71/2h, then how many articles will he make ?
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∵ In 2/3h, 1 article is made.
∴ In 1h, 3/2 article are made.Correct Option: A
∵ In 2/3h, 1 article is made.
∴ In 1h, 3/2 article are made.
∴ In 71/2 = 15/2h, 3/2 x 15/2 = 45/4 article are made.
∴ Required articles = 45/4 = 112/4
- 12 men can do a piece of work in 24 days. How many days are needed to complete the work, if 8 men are engaged in the same work ?
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Let the required number of days be N.
Let men, More days (indirect proportion)
8 : 12 : : 24 : NCorrect Option: B
Let the required number of days be N.
Let men, More days (indirect proportion)
8 : 12 : : 24 : N
∴ N = (12 x 24)/8 = 36 days
- If price of m articles is ₹ n, then what is the price of 5 articles ?
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∵ Price of m articles = ₹ n
∴ Price of 1 article = ₹ n/mCorrect Option: A
∵ Price of m articles = ₹ n
∴ Price of 1 article = ₹ n/m
∴ Price of 5 articles = ₹ 5n/m