Let the required number of flies be N.
More spiders, More flies (Direct proportion)
More time, More flies (Direct proportion)

Correct Option: C

Let the required number of flies be N.
More spiders, More flies (Direct proportion)
More time, More flies (Direct proportion)
∴ 10 x 10 x N = 200 x 200 x 10
∴ N = (200 x 200 x 10)/(10 x 10) = 4000 flies

M₁ = 12 H₁ = 16, W₁ = 33600
M₂ = 18, H₂ = 12, W₂ = ?
By formula, M₁H₁/W₁ = M₂H₂/W₂
(12 x 16)/33600 = (18 x 12)/W₂
⇒ W₂ = (33600 x 18)/16

Correct Option: D

M₁ = 12 H₁ = 16, W₁ = 33600
M₂ = 18, H₂ = 12, W₂ = ?
By formula, M₁H₁/W₁ = M₂H₂/W₂
(12 x 16)/33600 = (18 x 12)/W₂
⇒ W₂ = (33600 x 18)/16
⇒ W₂ = 2100 x 8
∴ W₂ = 37800

∵ For 1000 men, provision lasts for 48 days.
∴ For 1 men, provision lasts for (48 x 1000) days.
∴ For (1000 + 600) men, provision will last for (48 x 1000)/1600 days.

Correct Option: B

∵ For 1000 men, provision lasts for 48 days.
∴ For 1 men, provision lasts for (48 x 1000) days.
∴ For (1000 + 600) men, provision will last for (48 x 1000)/1600 days.
∴ Required number of days = (48 x 1000)/1600 = 3 x 10 = 30

Here M₁ = 30, D₁ = 16,
T₁ = 9, M₂ = 36 and T₂ = 8
By formula, M₁D₁T₁ = M₂D₂T₂

Correct Option: A

Here M₁ = 30, D₁ = 16,
T₁ = 9, M₂ = 36 and T₂ = 8
By formula, M₁D₁T₁ = M₂D₂T₂
30 x 16 x 9 = 36 x D₂ x 8
∴ D₂ = (30 x 16 x 9)/(36 x 8) = 15 days

∵ 22 men do the work in 16 days.
∴ 1 man will do the work in 16 x 22 days.

Correct Option: D

∵ 22 men do the work in 16 days.
∴ 1 man will do the work in 16 x 22 days.
∴ 32 men will do the job in = (16 x 22)/32 days
∴ Required number of days = (16 x 22)/32 = 11 days