Races and games


  1. In a race of 800 meter, A can beat B by 40 meter. In a race of 500 meter, B can beat C by 5 meter. In a race of 200 meter, A will beat C by









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    In a 800 meter race, A covers 800 meter while B cover 760 meter.
    ∴ A covers 200 m while B will cover 760 x 200 / 800 = 190 m

    Correct Option: B

    In a 800 meter race, A covers 800 meter while B cover 760 meter.
    ∴ A covers 200 m while B will cover 760 x 200 / 800 = 190 m
    Again, B covers 500 m while C 495 m
    ∴ B covers 190 m while C will cover = 495 x 190 / 500 = 188.10 m
    Since, A covers 200 m while C 188.10 m
    Hence, A will beat C by (200 – 188.10) = 11.9 m


  1. Shantanu started cycling along the boundaries of a square field ABCD from corner point A. After 1/2 h, he reached the corner point C, diagonally opposite to point A. If his speed was 16 km/h. Find the area of the field ?









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    Distance = (AB + BC) = 2L = 16 x 1/2 = 8 km
    ∴ L = 8/2 = 4 km

    Correct Option: D

    Distance = (AB + BC) = 2L = 16 x 1/2 = 8 km
    ∴ L = 8/2 = 4 km
    ∴ Area of the field = 4 x 4 = 16 sq km.



  1. In a 20 m race, A runs at a speed of 2 m/s. If A gives B a start of 10 m and still beats him by 5 s, what will be the speed of B?









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    Time taken by A to cover 200 m = 200/2 = 100 s
    ∴ B covers (200 - 10) = 190 m in (100 + 5) = 105 s

    Correct Option: A

    Time taken by A to cover 200 m = 200/2 = 100 s
    ∴ B covers (200 - 10) = 190 m in (100 + 5) = 105 s
    ∴ B' s speed = 190/105 = 38/21 = 117/21 m/s


  1. A runs 12/3 times as fast as B. If A gives B a start of 40 m, how far must the winning post be, so that A and B might reach it at the same time ?









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    Ratio of the speeds of A and B = 5 : 3
    Thus, in a race of 5 m, A gains 2 m over B.

    Correct Option: C

    Ratio of the speeds of A and B = 5 : 3
    Thus, in a race of 5m, A gains 2 m over B.
    2 m are gained by A in a race of 5 m.
    40 m will be gained by A in a race of (5/2) x 40 m = 100 m
    ∴ Winning post is 100 m away from the starting point.



  1. A 10 km race is organised at 800 m circular race course. P and Q are the contestants of the race. If the ratio of the speed of P and Q is 5 : 4, how many times will the winner overtake the loser ?









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    Speed of P : Speed of Q = 5 : 4
    Time taken by P to cover 5 rounds = Time taken by Q to cover 4 rounds
    Distance covered by P in 5 rounds = 5 x (800/1000) = 4 km
    Distance covered by Q in 4 rounds = 4 x (800/1000) = 16/5 km

    Correct Option: C

    Speed of P : Speed of Q = 5 : 4
    Time taken by P to cover 5 rounds = Time taken by Q to cover 4 rounds
    Distance covered by P in 5 rounds = 5 x (800/1000) = 4 km
    Distance covered by Q in 4 rounds = 4 x (800/1000) = 16/5 km

    In 5 rounds, P will overtake Q every time. It means that after covering 4 km, P will overtake Q one time .
    ∴ After covering 10 km P will overtake Q, = (1/4) x 10 = 21/2 times