Profit and Loss


  1. A person sold his watch for ₹ 75 and got a percentage profit equal to the cost price. The cost price of the watch is.









  1. View Hint View Answer Discuss in Forum

    Let CP of the watch be ₹ N.
    Then , According to the question,
    [(75 - N)/ N] x 100 = N

    Correct Option: C

    Let CP of the watch be ₹ N.
    Then , According to the question,
    [(75 - N)/ N] x 100 = N
    ⇒ (75 - N) x 100 = N2
    ⇒ N2 + 100N - 7500 = 0
    ⇒ N2 + 150N - 50N - 7500 = 0
    ⇒ N(N + 150) - 50 (N + 150) = 0
    ⇒ (N + 150) (N - 50) = 0
    ⇒ N = ₹ 50


  1. Two lots of onions with equal quantity, one costing ₹ 10 per kg and the other costing ₹ 15 per kg, are mixed together and whole lot is sold at ₹ 15 per kg. What is the profit or loss ?









  1. View Hint View Answer Discuss in Forum

    Let each lot of onion-contain N kg onion,
    Then total cost price of these two lots together = 10N + 15N = 25N
    Selling price of whole lot = 15 x (N + N) = 15 x 2N = 30N

    Correct Option: C

    Let each lot of onion-contain N kg onion,
    Then total cost price of these two lots together = 10N + 15N = 25N
    Selling price of whole lot = 15 x (N + N) = 15 x 2N = 30N
    Profit percentage = [(30N - 25N)/25N] x 100 %
    = (5/25) x 100%
    = 20%



  1. A vender sells lemons at the rate of 5 for ₹ 14. gaining thereby 40%. For how much did he buy a dozen lemon ?









  1. View Hint View Answer Discuss in Forum

    SP of 1 lemon = ₹ 14/5
    Let CP of 1 lemon = N
    According to the question, (N x 140)/100 = 14/5

    Correct Option: C

    SP of 1 lemon = ₹ 14/5
    Let CP of 1 lemon = N
    According to the question, (N x 140)/100 = 14/5
    ∴ N = ₹ 2
    ∴ CP for 12 lemons = 12 x 2 = 24


  1. By selling 32 orange for ₹ 30 a man loses 25%. How many oranges should be sold for ₹ 24 so as to gain 20% in the transaction ?











  1. View Hint View Answer Discuss in Forum

    Let the cost price be ₹ N.
    SP of 1 orange = ₹ 30/32 = ₹ 15/16

    According to the question, 75N/100 = 15/16
    ∴ N = [(15 x 100)/75] x 16 = ₹ 5/4

    SP of 1 orange with 20% profit = ₹ [(5/4) x 120]/100 = ₹ 3/2

    Correct Option: B

    Let the cost price be ₹ N.
    SP of 1 orange = ₹ 30/32 = ₹ 15/16

    According to the question, 75N/100 = 15/16
    ∴ N = [(15 x 100)/75] x 16 = ₹ 5/4

    SP of 1 orange with 20% profit = ₹ [(5/4) x 120]/100 = ₹ 3/2
    ∴ In ₹ 3/2, the number of oranges sold = 1
    ∴ in ₹ 24, the number of oranges sold = (2/3) x 24 = 16



  1. Kamlesh purchased 120 reams of paper at ₹ 100 per ream and the expenditure on transport was ₹ 480. He had to pay an octroi duty of 50 paise per ream and the coolie charges were ₹ 60. What should he charge per ream to gain 40% ?











  1. View Hint View Answer Discuss in Forum

    Total cost price = ₹ (120 x 100) = ₹ 12000
    Total expenditure = 480 + (1/2) x 120 + 60 = ₹ 600
    Total cost price = 12000 + 600 = ₹ 126000
    Gain = 40%
    SP of 120 reams = 12600 x (140/100)

    Correct Option: B

    Total cost price = ₹ (120 x 100) = ₹ 12000
    Total expenditure = 480 + (1/2) x 120 + 60 = ₹ 600
    Total cost price = 12000 + 600 = ₹ 126000
    Gain = 40%
    SP of 120 reams = 12600 x (140/100) = ₹ 17640
    ∴ SP per ream = 17640/120 = ₹ 147