Profit and Loss


  1. Niraj incurred a loss of 55% on selling an article for ₹ 9549. What was the cost price of the article ?









  1. View Hint View Answer Discuss in Forum

    Let cost price of article is CP.
    According to the formula,
    CP = [SP/(100 - Loss %)] x 100

    Correct Option: C

    Let cost price of article is CP.
    According to the formula,
    CP = [SP/(100 - Loss %)] x 100
    CP = [(100 x 9549)/(100 - 55)]
    = ₹ 21220


  1. Find the percentage loss when the cost price and selling price of an article are in the ratio of 5 : 3. ?











  1. View Hint View Answer Discuss in Forum

    Let CP = 5N and SP = 3N
    Loss = (CP- SP) = (5N - 3N) = 2N

    Correct Option: A

    Let CP = 5N and SP = 3N
    Loss = (CP- SP) = (5N - 3N) = 2N
    Loss % = (2N / 5N) x 100 %
    = 40%



  1. A shopkeeper sells eggs at 20 for a rupee gaining 30%. How many eggs did he buy for a rupee ?











  1. View Hint View Answer Discuss in Forum

    SP of 20 eggs = ₹ 1 and gain = 30%
    CP of 20 eggs = (1 x 100)/130 = ₹ 10/13
    Now, ₹ 10/13 yields 20 eggs.

    Correct Option: D

    SP of 20 eggs = ₹ 1 and gain = 30%
    CP of 20 eggs = (1 x 100)/130 = ₹ 10/13
    Now, ₹ 10/13 yields 20 eggs.
    ∴ ₹ 1 will yield (20 x 13)/10 = 26 eggs
    Clearly, 26 eggs were bought for ₹ 1.


  1. A man brought toffees at 6 for a rupee. How many toffees for a rupee must he sell to gain in 50%. ?











  1. View Hint View Answer Discuss in Forum

    CP of 6 toffees = ₹ 1,
    SP of 6 toffees = 150% of 1 = 150/100 = 3/2

    Correct Option: C

    CP of 6 toffees = ₹ 1,
    SP of 6 toffees = 150% of 1 = 150/100 = 3/2
    ∵ For ₹ 3/2, the number of toffees sold = 6
    ∴ For ₹ 1, the number of toffees sold = 6 x (2/3) = 4



  1. A merchant fixed the selling price of his articles at ₹ 700 after adding 40% profit to the cost price. As the sale was very low at this price level, he decided to fix at the selling price at 10% profit. Find the new selling price









  1. View Hint View Answer Discuss in Forum

    Let cost price = ₹ N
    According to the question,
    N x [(100 + 40)/100] = 700,

    Correct Option: D

    Let cost price = ₹ N
    According to the question,
    N x [(100 + 40)/100] = 700,
    ⇒ N = (700 x 100)/140 = 500
    ∴ New selling price = 500 x (100 + 10)/100
    = 5 x 110 = 550
    = ₹ 550