Problem on Trains
- Two trains of same length take 6 s and 9 s, respectively to cross a pole. If both the trains are running in the same direction, then how long will they take to cross each other ?
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Given that, t1 = 6 s and t2 = 9 s
Then, time taken by the trains to cross each other = 2t1 t2 / (t2 - t1)Correct Option: B
Given that, t1 = 6 s and t2 = 9 s
Then, time taken by the trains to cross each other = 2t1 t2 / (t2 - t1)
= (2 x 6 x 9)/(9 - 6) = 36 s
- Two station P and Q are at a distance of 160 km. Two trains starts moving from P and Q to Q and P respectively and meet each other after 4 h . If speed of the train starting from P is more than that of other train by 6 km/h. then find the speeds of both the trains, respectively. ?
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Let the speed of both trains be V km/h and (V + 6) km/h, respectively
Then, according to the question.
160 = V x 4 + (V + 6) x 4Correct Option: C
Let the speed of both trains be V km/h and (V + 6) km/h, respectively
Then, according to the question.
160 = V x 4 + (V + 6) x 4
⇒ 160 = 4V + 4V + 24
⇒ 40 = V + V + 6
⇒ 2V + 6 = 40
⇒ 2V = 34
∴ V = 17
Hence, speeds of both the trains are 17 km/h and (17 + 6 ) km/h i,e 17 km/h and 23 km/h .
- P and Q are 27 km away. Two trains will having speeds of 24 km/h and 18 km/h respectively starts simultaneously from P and Q and travel in the same direction. They meet at a point R beyond Q. Distance QR is
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If the trains meet after t h.
Relative speed of train = (24 -18) = 6 km/h
⇒ Distance = 27
∴ t = 27/6 = 9/2 hCorrect Option: B
If the trains meet after t h.
Relative speed of train = (24 -18) = 6 km/h
⇒ Distance = 27
∴ t = 27/6 = 9/2 h
∴ QR distance travel by train which is travelling at a speed of 18 km/h = 18t = 18 x 9/2 = 81 km
- Two train start at the same time from points x and y towards each other and after crossing, they take 9 h and 4 h in reaching points y and x, respectively. Find the ratio of speeds of the 1st train to that of the 2nd train ?
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Given that, T1 = 9 h and T 2 = 4 h
According to the formula.
(1st train's speed) : (2nd train's speed) = √4 : √9Correct Option: A
Given that, T1 = 9 h and T 2 = 4 h
According to the formula.
(1st train's speed) : (2nd train's speed) = √4 : √9
= 2 : 3
- Two trains are running 40 km/h and 20 km/h respectively, in the same directions. The fast train completely passes a man sitting in the slow train in 5 s. The length of the fast a train is ?
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The length of the fast train = Relative speed x Time
= (40 - 20) x (5/18) x 5Correct Option: C
The length of the fast train = Relative speed x Time
= (40 - 20) x (5/18) x 5 = 277/9 m