Problem on Trains
- A train running at the speed of 45 kmph took 12 seconds in passing a certain point. Then the length of the train must be ?
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∵ Speed = (45 x 5/18) = (25/2) m/sec
Distance = (Time x Speed)Correct Option: C
∵ Speed = (45 x 5/18) = (25/2) m/sec
Distance = (Time x Speed) = (12 x 25 / 2 ) meters
= 150 meters
∴ Length of the train = 150 meters
- 150 meter long train takes 10 second two pass a man who is going in same direction at the speed of 2 km/hr . What is the speed of the train ?
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Let the speed of the train be Y km/hr
∴ length of the train = 150 m
= 150/1000 = 3/20 km.
Time taken to cross the man = 10 seconds
= 10/ (60 x 60) = 1/360 hrs .
∵ time = Length of the train /( speed of the train - speed of the man )
∴ 1/360 = ( 3 / 20) / ( Y - 2)Correct Option: B
Let the speed of the train be Y km/hr
∴ length of the train = 150 m
= 150/1000 = 3/20 km.
Time taken to cross the man = 10 seconds
= 10/ (60 x 60) = 1/360 hrs .
∵ time = Length of the train /( speed of the train - speed of the man )
∴ 1/360 = ( 3 / 20) / ( Y - 2)
⇒ (Y - 2 ) = 3/20 x 360
⇒ (Y - 2 )= 54
⇒ Y = 54 + 2
= 56 km/hr.
- X and Y are two station 500 km apart. A train start from X and moves toward Y at 20 km/hr another train station from Y at the same times and moves toward X at 30 km/hr. How far from X will they cross each other ?
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Suppose they meet x km. from X
Then, x/20 = (500 - x)/30Correct Option: A
Suppose they meet x km. from X
Then, x/20 = (500 - x)/30
⇒ 30x = 10000 - 20x
∴ x = 200 km.
- A train with 90 km/hr crosses a bridge in 36 seconds. Another train 100 m shorter crosses the same bridge at 45 km/hr. Find the time taken by the second train to cross the bridge ?
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Speed of the first train = 90 km/hr = 90 x (5/18) m/sec. = 25 m/sec
Let the length of the train and bridge be L metre.
∴ L = 25 x 36 = 900 m.....(1)Correct Option: A
Speed of the first train = 90 km/hr = 90 x (5/18) m/sec. = 25 m/sec
Let the length of the train and bridge be L metre.
∴ L = 25 x 36 = 900 m.....(1)
Again Speed of the second train = 45 km/hr = 45 x (5/18) = 25/2 m/sec.
Now, putting the value from eqn. (1) we have
Time taken = (900 - 100) x 2/25 = 800 x 2/25 = 64 sec
- A train crosses a platform in 30 s travelling with a speed of 60 km/h. If the length of the train be 200 m, then the length of the platform is ?
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Speed of train = 60 km/h = 60 x (5/18) m/s = 50/3 m/s
Let length of the platform be L m.
According to the question,
200 + L = (50/3) x 30Correct Option: C
Speed of train = 60 km/h = 60 x (5/18) m/s = 50/3 m/s
Let length of the platform be L m.
According to the question,
200 + L = (50/3) x 30
⇒ 200 + L = 500
∴ L = 300 m