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Two station P and Q are at a distance of 160 km. Two trains starts moving from P and Q to Q and P respectively and meet each other after 4 h . If speed of the train starting from P is more than that of other train by 6 km/h. then find the speeds of both the trains, respectively. ?
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- 19 km/h, 13 km/h
- 13 km/h, 9 km/h
- 17 km/h, 23 km/h
- 16 km/h, 10 km/h
Correct Option: C
Let the speed of both trains be V km/h and (V + 6) km/h, respectively
Then, according to the question.
160 = V x 4 + (V + 6) x 4
⇒ 160 = 4V + 4V + 24
⇒ 40 = V + V + 6
⇒ 2V + 6 = 40
⇒ 2V = 34
∴ V = 17
Hence, speeds of both the trains are 17 km/h and (17 + 6 ) km/h i,e 17 km/h and 23 km/h .
