Percentage

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Aptitude miscellaneous
  1. 48% of the 1st number is 60% of the 2nd number. What is the ratio of the 1st number to the 2 nd number?










  1. View Hint View Answer Discuss in Forum

    Let 1st number be M and 2nd number be M.
    According to the question,
    48% of M = 60% N
    ⇒ (M x 48)/100 = (N x 60)/100

    Correct Option: C

    Let 1st number be M and 2nd number be M.
    According to the question,
    48% of M = 60% N
    ⇒ (M x 48)/100 = (N x 60)/100
    ⇒ M/N = (60/100) x (100/48) = 5/4
    ∴ M : N = 5 : 4

  1. The sum of 15% of a positive number and 20% of the same number is 126. What is one-third of that number










  1. View Hint View Answer Discuss in Forum

    Let the positive number be N.

    According to the question
    N x (15+ 20)% = 126
    ⇒ N x 35 = 126 x 100

    Correct Option: C

    Let the positive number be N.

    According to the question
    N x (15+ 20)% = 126
    ⇒ N x 35 = 126 x 100
    ∴ N = 12600/35 = 360
    So, one-third of the number = 360/3 = 120

  1. In a test, A scored 10% more than B and B scored 5% more than C. If C scored 300 marks out of 400, then A's marks are








  1. View Hint View Answer Discuss in Forum

    B's marks = C's marks + 5% of 400
    = 300 + 20 = 320

    Now , A's marks = B's marks + 10% of 400

    Correct Option: D

    B's marks = C's marks + 5% of 400
    = 300 + 20 = 320

    Now , A's marks = B's marks + 10% of 400
    = 320 + 40 = 360

  1. Mathew scored 42 marks in Biology, 51 marks in Chemistry, 58 marks in Mathematics, 35 marks in Physics and 48 marks English. The maximum marks, a student can score in each subject, are 60. How much overall percentage did Mathew get in this exam ?










  1. View Hint View Answer Discuss in Forum

    Total marks scored by Mathew in all subjests = 42 + 51 + 58 + 35 + 48 = 234
    ∵ Maximum marks is 60 in any subject.
    ∴ Maximum marks = 60 x 5 = 300
    ∴ Percentage of Mathew's marks
    = [(Marks obtained / Maximum marks)] x 100

    Correct Option: D

    Total marks scored by Mathew in all subjests = 42 + 51 + 58 + 35 + 48 = 234
    ∵ Maximum marks is 60 in any subject.
    ∴ Maximum marks = 60 x 5 = 300
    ∴ Percentage of Mathew's marks
    = [(Marks obtained / Maximum marks)] x 100
    = (234 / 300) x 100
    = 234/3 = 78%

  1. A student was asked to measure the length and breadth of a rectangle. By mistake, he measured the length 20% less and the breath 10% more. if its original area is 200 sq cm, then find the area after this measurement ?










  1. View Hint View Answer Discuss in Forum

    Net effect on area = -20 + 10 + [(-20 )(10)/100] %
    = (-10 - 2) % = -12%
    Now, after this mistake new area = (100 - 12)% of 200
    = (88/100) x 200

    Correct Option: A

    Net effect on area = -20 + 10 + [(-20 )(10)/100] %
    = (-10 - 2) % = -12%
    Now, after this mistake new area = (100 - 12)% of 200
    = (88/100) x 200
    = 176 sq cm