Percentage
- In a school, 10% of boys are equal to the one - fourth of the girls. What is the ration of boys and girls in that school?
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Let the number of boys = B
and number of girls = G
Then, 10% of B = 1/4 of GCorrect Option: B
Let the number of boys = B
and number of girls = G
Then, 10% of B = 1/4 of G
⇒ B/10 = G/4
⇒ B/G = 10/4 = 5/2
⇒ B : G = 5 : 2
- In a test, A scored 10% more than B and B scored 5% more than C. If C scored 300 marks out of 400, then A's marks are
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B's marks = C's marks + 5% of 400
= 300 + 20 = 320
Now , A's marks = B's marks + 10% of 400Correct Option: D
B's marks = C's marks + 5% of 400
= 300 + 20 = 320
Now , A's marks = B's marks + 10% of 400
= 320 + 40 = 360
- A student was asked to measure the length and breadth of a rectangle. By mistake, he measured the length 20% less and the breath 10% more. if its original area is 200 sq cm, then find the area after this measurement ?
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Net effect on area = -20 + 10 + [(-20 )(10)/100] %
= (-10 - 2) % = -12%
Now, after this mistake new area = (100 - 12)% of 200
= (88/100) x 200Correct Option: A
Net effect on area = -20 + 10 + [(-20 )(10)/100] %
= (-10 - 2) % = -12%
Now, after this mistake new area = (100 - 12)% of 200
= (88/100) x 200
= 176 sq cm
- Mathew scored 42 marks in Biology, 51 marks in Chemistry, 58 marks in Mathematics, 35 marks in Physics and 48 marks English. The maximum marks, a student can score in each subject, are 60. How much overall percentage did Mathew get in this exam ?
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Total marks scored by Mathew in all subjests = 42 + 51 + 58 + 35 + 48 = 234
∵ Maximum marks is 60 in any subject.
∴ Maximum marks = 60 x 5 = 300
∴ Percentage of Mathew's marks
= [(Marks obtained / Maximum marks)] x 100Correct Option: D
Total marks scored by Mathew in all subjests = 42 + 51 + 58 + 35 + 48 = 234
∵ Maximum marks is 60 in any subject.
∴ Maximum marks = 60 x 5 = 300
∴ Percentage of Mathew's marks
= [(Marks obtained / Maximum marks)] x 100
= (234 / 300) x 100
= 234/3 = 78%
- A candidate scores 20% and fails by 50 marks, while another candidate who score 40% marks, gests 30 marks more than the minimun required marks to pass the examination. Find the maximum marks for the examination.
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Let the maximum marks be N.
According to the question,
(20N/100) + 50 = (40N/100) - 30Correct Option: D
Let the maximum marks be N.
According to the question,
(20N/100) + 50 = (40N/100) - 30
⇒ 20N/100 = 80
∴ N = (80 x 100)/20 = 400