Percentage


  1. In a school, 10% of boys are equal to the one - fourth of the girls. What is the ration of boys and girls in that school?









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    Let the number of boys = B
    and number of girls = G
    Then, 10% of B = 1/4 of G

    Correct Option: B

    Let the number of boys = B
    and number of girls = G
    Then, 10% of B = 1/4 of G
    ⇒ B/10 = G/4
    ⇒ B/G = 10/4 = 5/2
    ⇒ B : G = 5 : 2


  1. In a test, A scored 10% more than B and B scored 5% more than C. If C scored 300 marks out of 400, then A's marks are









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    B's marks = C's marks + 5% of 400
    = 300 + 20 = 320

    Now , A's marks = B's marks + 10% of 400

    Correct Option: D

    B's marks = C's marks + 5% of 400
    = 300 + 20 = 320

    Now , A's marks = B's marks + 10% of 400
    = 320 + 40 = 360



  1. A student was asked to measure the length and breadth of a rectangle. By mistake, he measured the length 20% less and the breath 10% more. if its original area is 200 sq cm, then find the area after this measurement ?











  1. View Hint View Answer Discuss in Forum

    Net effect on area = -20 + 10 + [(-20 )(10)/100] %
    = (-10 - 2) % = -12%
    Now, after this mistake new area = (100 - 12)% of 200
    = (88/100) x 200

    Correct Option: A

    Net effect on area = -20 + 10 + [(-20 )(10)/100] %
    = (-10 - 2) % = -12%
    Now, after this mistake new area = (100 - 12)% of 200
    = (88/100) x 200
    = 176 sq cm


  1. Mathew scored 42 marks in Biology, 51 marks in Chemistry, 58 marks in Mathematics, 35 marks in Physics and 48 marks English. The maximum marks, a student can score in each subject, are 60. How much overall percentage did Mathew get in this exam ?











  1. View Hint View Answer Discuss in Forum

    Total marks scored by Mathew in all subjests = 42 + 51 + 58 + 35 + 48 = 234
    ∵ Maximum marks is 60 in any subject.
    ∴ Maximum marks = 60 x 5 = 300
    ∴ Percentage of Mathew's marks
    = [(Marks obtained / Maximum marks)] x 100

    Correct Option: D

    Total marks scored by Mathew in all subjests = 42 + 51 + 58 + 35 + 48 = 234
    ∵ Maximum marks is 60 in any subject.
    ∴ Maximum marks = 60 x 5 = 300
    ∴ Percentage of Mathew's marks
    = [(Marks obtained / Maximum marks)] x 100
    = (234 / 300) x 100
    = 234/3 = 78%



  1. A candidate scores 20% and fails by 50 marks, while another candidate who score 40% marks, gests 30 marks more than the minimun required marks to pass the examination. Find the maximum marks for the examination.











  1. View Hint View Answer Discuss in Forum

    Let the maximum marks be N.

    According to the question,
    (20N/100) + 50 = (40N/100) - 30

    Correct Option: D

    Let the maximum marks be N.

    According to the question,
    (20N/100) + 50 = (40N/100) - 30
    ⇒ 20N/100 = 80
    ∴ N = (80 x 100)/20 = 400