Logarithm
- If log (x + 4) = log(4) + log(x) and log (x + 6) = log (6) then which of the following correct ?
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Given log (x + 4) = log(4) + log(x)
⇒ x + 4 = 4x
∴ x = 4/3
Similarly y = 5/4Correct Option: C
Given log (x + 4) = log(4) + log(x)
⇒ x + 4 = 4x
∴ x = 4/3
Similarly y = 5/4
∴ x > y
- If log(x - 5) = log(x) - log(5) and log(y - 6) = log(y) - log(6) then which of the following is correct ?
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Given log( x - 5) = log(x) - log(5)
⇒ x -5 = x/5
∴ x = 25/ 4 ....(i)
Again from question
log(y - 6) = log(y) - log(6)
⇒ y - 6 = y/6
∴ y = 36/5 ...(ii)Correct Option: B
Given log( x - 5) = log(x) - log(5)
⇒ x -5 = x/5
∴ x = 25/ 4 ....(i)
Again from question
log(y - 6) = log(y) - log(6)
⇒ y - 6 = y/6
∴ y = 36/5 ...(ii)
From equations (i) & (ii) x < y
- Find the no. of digits in 857 (given that log102 = 0.3010)
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857 = (23)57 = 2171
∴ Required answer = (171 log10 2 + 1 )
Correct Option: A
857 = (23)57 = 2171
∴ Required answer = (171 log10 2 + 1 )
= [171 x 0.3010] + 1 = [51.4710] +1
= 51+1 =52
- Find the number of digits in 810 ? (Given that log10 2 = 0.3010)
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810 = (23)10
∴ Required answer = [30 log10 2 + 1]Correct Option: D
810 = (23)10
∴ Required answer = [30 log10 2 + 1]
= [30 x 0.3010] + 1
= 9.03 + 1
= 9 + 1
= 10