Since, 0.3274 gives characteristic 1. Therefore value of log (0.3274) = 1.5150

Correct Option: A

Since, 0.3274 gives characteristic 1. Therefore value of log (0.3274) = 1.5150

∵ loga, logb, logc are in A.P. Then,
⇒ logb - loga = logc - logb

Correct Option: A

∵ loga, logb, logc are in A.P. Then,
⇒ logb - loga = logc - logb
⇒ log b/a = log c/b
⇒ b/a = c/b
⇒ b² = ac
∴ a, b, c are in G.P.

∵ log₅(x² + x / x) = 2
⇒ log₁₀(x + 1) = 2

Correct Option: A

∵ log₅[(x² + x ) / x] = 2
⇒ log₁₀(x + 1) = 2
⇒ x + 1 = 25
∴ x = 24

∵ A = 12,000(1 + 12/100)¹⁰
= 12000(28/25)¹⁰
⇒ log A = log 12000 + 10[log 28 - log 25]
⇒ log A = 4.0792 + 10(1.4472 - 1.3979)
= 4.0792 + 0.493

Correct Option: A

∵ A = 12,000(1 + 12/100)¹⁰
= 12000(28/25)¹⁰
⇒ log A = log 12000 + 10[log 28 - log 25]
⇒ log A = 4.0792 + 10(1.4472 - 1.3979)
= 4.0792 + 0.493
= 4.5722
∴ A = antilog 4.5722 = 37342
C.I. = 37342 - 12000 = 25342
=25350

∵ log tan 45 = log 1 = 0

Correct Option: A

∵ log tan 45 = log 1 = 0
Hence, Whole Expression = (something) x zero