1992 being a leap year, it has 2 odd days. So, the first day of the year 1993 will be two days beyond Wednesday i.e., it will be Friday.

Correct Option: D

1992 being a leap year, it has 2 odd days. So, the first day of the year 1993 will be two days beyond Wednesday i.e., it will be Friday.

1600 years of 0 odd days and 30 years have 1 odd day. 49 years contain 12 leap years and 37 ordinary years and therefore (24 + 37) odd days i.e., 5 odd days i.e., 1949 years contain (0 + 1 + 5) = 6 odd days. 26 day of January contain 5 days.Total odd days = (6 + 5) = 11 or 4 days. So, the days was Thursday

Correct Option: C

1600 years of 0 odd days and 30 years have 1 odd day. 49 years contain 12 leap years and 37 ordinary years and therefore (24 + 37) odd days i.e., 5 odd days i.e., 1949 years contain (0 + 1 + 5) = 6 odd days. 26 day of January contain 5 days.Total odd days = (6 + 5) = 11 or 4 days. So, the days was Thursday

This being a leap year none of the next 3 year is a leap year. So, the day of the week will be 3 days beyond Monday.

Correct Option: B

This being a leap year none of the next 3 year is a leap year. So, the day of the week will be 3 days beyond Monday i.e., it will be Thursday.

Clock will make right angle at (5n + 15) x 12/11 min past n.
Given that, n = 3

Correct Option: D

Clock will make right angle at (5n + 15) x 12/11 min past n.
Given that, n = 3
∴ Clock will make right angle at ( 5 x 3 + 15 ) x 12/11 min past 3 . =30 x 12 / 11 min past 3.
= 32⁸/₁₁ min
So required time = 3 H 32⁸/₁₁ min

Angle traced by hour hand in 12 h = 360°
Angle traced by hour hand in 25/4 h = ( 360/12) x (25/4)° = 187.5°
Angle traced by minute hand in 60 min = 360°
Angle traced by it in 15 min = (360/60) x 15° = 90°

Correct Option: C

Angle traced by hour hand in 12 h = 360°
Angle traced by hour hand in 25/4 h = (360/12) x (25/4)° = 187.5°
Angle traced by minute hand in 60 min = 360°
Angle traced by it in 15 min = (360/60) x 15° = 90°
∴ Required angle = (187.5° - 90°) = 97.5°