On 31 st December, 2005 it was Saturday, Number of odd days from the year 2006 to the year 2009
= 1 odd day of 2006 + 1 odd day of 2007 + 2 odd days of 2008 (leap year) + 1 odd day of 2009
= 1 + 1 + 2 + 1 = 5

Correct Option: A

On 31 st December, 2005 it was Saturday, Number of odd days from the year 2006 to the year 2009
= 1 odd day of 2006 + 1 odd day of 2007 + 2 odd days of 2008 (leap year) + 1 odd day of 2009
= 1 + 1 + 2 + 1 = 5
∴ On 31st December 2009, it was Thursday
Thus, on 2nd January 2010, it was Saturday .

6th March 2005 = Monday.
Then, 6th March 2004 = Monday - 1 days = Sunday.
(2004 is a leap year but it does not cross 29th February of 2004, so only 1 is taken as odd day).

Correct Option: B

6th March 2005 = Monday.
Then, 6th March 2004 = Monday - 1 days = Sunday.
(2004 is a leap year but it does not cross 29th February of 2004, so only 1 is taken as odd day).
6th March 2004 = Sunday
7th March 2004 = Monday.

5th March, 1999 is Friday.
Then, 5 March 2000 = Friday + 2 = Sunday
(2000 is leap year and it crosses 29th feb 2000, so 2 is taken as odd day}

Correct Option: D

5th March, 1999 is Friday.
Then, 5 March 2000 = Friday + 2 = Sunday
(2000 is leap year and it crosses 29th feb 2000, so 2 is taken as odd day}

∴ 5th March 2000 = Sunday
Then, 9th March 2000 = Thursday.

The year 2008 is a leap year, so it has 2 odd days, 3rd day of the year 2008 was Friday.
∴ 3rd day of the year 2009 will be 2 days beyond the Friday.

Correct Option: A

The year 2008 is a leap year, so it has 2 odd days, 3rd day of the year 2008 was Friday.
∴ 3rd day of the year 2009 will be 2 days beyond the Friday.
Hence, the required answer is Sunday.

The year 2007 is an ordinary year, so it has 1 odd day.
3rd day of the year 2007 was Wednesday.
∴ 3rd day of the year 2008 will be one day beyond the Wednesday.

Correct Option: C

The year 2007 is an ordinary year, so it has 1 odd day.
3rd day of the year 2007 was Wednesday.
∴ 3rd day of the year 2008 will be one day beyond the Wednesday. Hence, it will be Thursday.