Clocks and Calendars
- How many times do the hands of a clock point towards each other in a day?
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According to question , we know that
The hands of a clock point towards each other 11 times in every 12 hours. (because between 5 and 7, at 6 O’clock only they point towards each other) .Correct Option: D
According to question , we know that
The hands of a clock point towards each other 11 times in every 12 hours. (because between 5 and 7, at 6 O’clock only they point towards each other)
So, in a day the hands point towards each other 22 times.
Hence , correct answer will be 22 times.
- Mahatma Gandhi was born on October 2, 1869. The day of the week was:
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As we know that ,
2 October 1869 means = 1868 complete years + 9 months + 2 days
1600 years give 0 odd days
200 years give 3 odd daysNumber of leap years in 68 years = largest integer less than 68 = 17 . 4
∴ 68 years contain 17 leap years and 51 non‑ leap years:
∴ 68 years have [ ( 2 × 17 ) + 51 ] = 85 days = ( 12 x 7 + 1 ) = 1 odd day
Also count number of days from January 1, 1869 to October 2, 1869 = January + February + March + April + May + June + July August + September + October = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 2 = 275 days = 39 weeks + 2 days
∴ This gives 2 odd days
Correct Option: C
As we know that ,
2 October 1869 means = 1868 complete years + 9 months + 2 days
1600 years give 0 odd days
200 years give 3 odd daysNumber of leap years in 68 years = largest integer less than 68 = 17 . 4
∴ 68 years contain 17 leap years and 51 non‑ leap years:
∴ 68 years have [ ( 2 × 17 ) + 51 ] = 85 days = ( 12 x 7 + 1 ) = 1 odd day
Also count number of days from January 1, 1869 to October 2, 1869 = January + February + March + April + May + June + July August + September + October = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 2 = 275 days = 39 weeks + 2 days
∴ This gives 2 odd days
∴ Total number of odd days = 0 + 3 + 1 + 2 = 6
Hence , Day on October 2, 1869 was Saturday.
- On what date of August, 1988 did Friday fall?
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We can say that ,
August 1, 1988 means = 1987 years + 7 months
Number of odd days in 1987 years = 1600 years have 0 odd days + 300 years have 1 odd day + 87 years have 21 leap years and 66 ordinary years.
So, there are [ ( 21 × 2 ) + ( 66 × 1 ) ] = 108 days, = 15 weeks and 3 odd days.
Number of days between January 1, 1988 to August 1, 1989 = January + February + March + April + May + June + July + August = 31 + 29 + 31 + 30 + 31 + 30 + 31 + 1 = 241 days = 30 weeks and 4 odd days.Correct Option: A
We can say that ,
August 1, 1988 means = 1987 years + 7 months
Number of odd days in 1987 years = 1600 years have 0 odd days + 300 years have 1 odd day + 87 years have 21 leap years and 66 ordinary years.
So, there are [ ( 21 × 2 ) + ( 66 × 1 ) ] = 108 days, = 15 weeks and 3 odd days.
Number of days between January 1, 1988 to August 1, 1989 = January + February + March + April + May + June + July + August = 31 + 29 + 31 + 30 + 31 + 30 + 31 + 1 = 241 days = 30 weeks and 4 odd days.
Total number of odd days = 0 + 1 + 3 + 4 = 8 odd days = ( 1 x 7 + 1 ) = 1 odd day.
Thus, Friday falls on 5th, 12th, 19th and 26th in August 1988.
- If the seventh day of a month is three days earlier than Friday, what day will be on the nineteenth day of the month ?
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Three days earlier than Friday means Tuesday.
So, 7th day of month will be Tuesday.Correct Option: A
Three days earlier than Friday means Tuesday.
So, 7th day of month will be Tuesday.
14th day of month will be Tuesday.
19th day of month will be Sunday.
- On January 12, 1980, it was Saturday. The day of the week on January 12, 1980, it was Saturday. The day of the week on January 12, 1979 was ?
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The year 1979 being an ordinary year, it has 1 odd day. So, the day on 12th January, 1979
But January 12, 1980 being Saturday
∴ January 12, 1979 was Friday.Correct Option: B
The year 1979 being an ordinary year, it has 1 odd day. So, the day on 12th January, 1979
But January 12, 1980 being Saturday
∴ January 12, 1979 was Friday.
