Average


  1. After replacing an old member by a new member, it was found that the average age of five members of a club is the same as it was 3 years ago. The difference between the ages of the replaced and the new members is









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    According to question ,
    Increase in ages of five members in 3 years = (3 × 5) years = 15 years
    As average age remains same,

    Correct Option: D

    According to question ,
    Increase in ages of five members in 3 years = (3 × 5) years = 15 years
    As average age remains same,
    ∴ Required difference = 15 years


  1. Three years ago, the average age of a family of 5 members was 17 years. A baby having been born the average age of the family is the same today. The present age of the baby (in years) is









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    Here , Three years ago, the average age of 5 members = 17 years
    Three years ago, Total age of the family = 17 × 5 = 85 years
    Total age of 5 member family today = 85 + 15 = 100 years
    Born on baby , the average age of 6 members = 17 years
    Total age of the family with child today = 17 × 6 = 102 years

    Correct Option: A

    Here , Three years ago, the average age of 5 members = 17 years
    Three years ago, Total age of the family = 17 × 5 = 85 years
    Total age of 5 member family today = 85 + 15 = 100 years
    Born on baby , the average age of 6 members = 17 years
    Total age of the family with child today = 17 × 6 = 102 years
    Age of baby = 102 – 100 = 2 years



  1. Three years ago, the average age of a family of 5 members was 17 years. A baby having been born, the average age of the family is the same today. The present age of the baby is:









  1. View Hint View Answer Discuss in Forum

    Here , Three years ago, the average age of 5 members = 17 years.
    Total age of the family 3 years ago = 5 × 17 = 85 years
    Total present age of the family = 85 + 15 = 100 years
    Let the child’s present age be y years.
    According to the question,
    100 + y = 17 × 6 = 102

    Correct Option: A

    Here , Three years ago, the average age of 5 members = 17 years.
    Total age of the family 3 years ago = 5 × 17 = 85 years
    Total present age of the family = 85 + 15 = 100 years
    Let the child’s present age be y years.
    According to the question,
    100 + y = 17 × 6 = 102
    ⇒ y = 102 – 100 = 2 years
    Hence , the child’s present age is 2 years.


  1. Numbers of boys and girls are ‘x’ and ‘y’ respectively. Ages of a girl and a boy are ‘a’ years and ‘b’ years respectively. The average age (in years) of all boys and girls is









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    According to question ,
    Total age of boys = ap years
    Total age of girls = bq years

    Correct Option: C

    According to question ,
    Total age of boys = ap years
    Total age of girls = bq years

    ∴ Required average = ap + bq
    p + q



  1. A man had 7 children. When their average age was 12 years, a child aged 6 years died. The average age of remaining six children is









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    Here , The average age of 7 children = 12
    Total age of 7 children = 12 × 7
    Age of died child = 6 years
    Total age of remaining 6 children = 12 × 7 – 6 = 84 – 6
    Total age of remaining 6 children = 78 years

    Correct Option: A

    Here , The average age of 7 children = 12
    Total age of 7 children = 12 × 7
    Age of died child = 6 years
    Total age of remaining 6 children = 12 × 7 – 6 = 84 – 6
    Total age of remaining 6 children = 78 years
    ∴ Their average age = 78 ÷ 6 = 13 years