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Aptitude miscellaneous
  1. Out of 4 numbers, whose average is 60, the first one is onefourth of the sum of the last three. The first number is








  1. View Hint View Answer Discuss in Forum

    Let the first number be p,

    then, p =
    240 - x
    		 = 48
    4

    ⇒ 4p = 240 – p

    Correct Option: C

    Let the first number be p,

    then, p =
    240 - x
    		 = 48
    4

    ⇒ 4p = 240 – p
    ⇒ 5p = 240
    ⇒ p = 240 ÷ 5 = 48

  1. The average of first three numbers is thrice the fourth number. If the average of all the four numbers is 5, then find the fourth number.








  1. View Hint View Answer Discuss in Forum

    Let the numbers be a, b, c.
    According to question ,

    a + b + c
    		= 3d
    3

    &trArr; a + b + c = 9d .........( 1 )
    Again,
    a + b + c + d
    		= 5
    4

    Correct Option: C

    Let the numbers be a, b, c.
    According to question ,

    a + b + c
    		= 3d
    3

    &trArr; a + b + c = 9d .........( 1 )
    Again,
    a + b + c + d
    		= 5
    4

    ⇒ a + b + c + d = 20
    ⇒ 9d + d = 20 { ∴ from eq. ( 1 ) }
    ⇒ 10d = 20
    ⇒ d = 2

  1. The average monthly income of A and B is ₹ 14000, that of B and C is ₹ 15600 and A and C is ₹ 14400. The monthly income of C is








  1. View Hint View Answer Discuss in Forum

    Given , The average monthly income of A and B = ₹ 14000
    ⇒ A + B = 28,000 ...(i)
    The average monthly income of B and C = ₹ 15600
    ⇒ B + C = 31,200 ...(ii)
    The average monthly income of A and C = ₹ 14400
    ⇒ C + A = 28,800 ...(iii)
    Adding, 2(A + B + C) = 88000
    ⇒ A + B + C = 44000

    Correct Option: A

    Given , The average monthly income of A and B = ₹ 14000
    ⇒ A + B = 28,000 ...(i)
    The average monthly income of B and C = ₹ 15600
    ⇒ B + C = 31,200 ...(ii)
    The average monthly income of A and C = ₹ 14400
    ⇒ C + A = 28,800 ...(iii)
    Adding, 2(A + B + C) = 88000
    ⇒ A + B + C = 44000
    From equation (i),
    28000 + C = 44000
    ⇒ C = 44000 – 28000 = 16000

  1. The average of 25 consecutive odd integers is 55. The highest of these integers is








  1. View Hint View Answer Discuss in Forum

    Here , Average of 25 consecutive odd numbers = 55
    ∴ Mid number i.e. 13th number = 55

    Correct Option: A

    Here , Average of 25 consecutive odd numbers = 55
    ∴ Mid number i.e. 13th number = 55
    ∴ 25th number = 55 + 2 × 12
    25th number = 55 + 24 = 79

  1. If the average of 6 consecutive even numbers is 25, the difference between the largest and the smallest number is








  1. View Hint View Answer Discuss in Forum

    Let Numbers = y , y + 2, ...., y + 10
    ∴ Required difference = largest number - smallest number

    Correct Option: B

    Let Numbers = y , y + 2, ...., y + 10
    ∴ Required difference = largest number - smallest number
    Required difference = y + 10 – y = 10