Average
- A batsman in his 12th innings makes a score of 63 runs and there by increases his average scores by 2. What is his average after the 12th innings?
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A batsman in his 12th innings makes a score = 63 runs
And there by increases his average scores = 2
Extra runs = 12 × 2 = 24Correct Option: B
A batsman in his 12th innings makes a score = 63 runs
And there by increases his average scores = 2
Extra runs = 12 × 2 = 24
∴ Required average = 63 – 24 = 39
- In a 20 over match, the required run rate to win is 7.2. If the run rate is 6 at the end of the 15th over, the required run rate to win the match is
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Here , In a 20 over match, the required run rate to win = 7.2
Total runs = 20 × 7.2 = 144
Total runs in 15 overs = 15 × 6 = 90
Runs to be scored in the next 5 overs = 144 – 90 = 54Correct Option: C
Here , In a 20 over match, the required run rate to win = 7.2
Total runs = 20 × 7.2 = 144
Total runs in 15 overs = 15 × 6 = 90
Runs to be scored in the next 5 overs = 144 – 90 = 54
∴ Required run-rate = 54 ÷ 5 = 10.8
- A cricketer has a mean score of 60 runs in 10 innings. Find out how many runs are to be scored in the eleventh innings to raise the mean score to 62?
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Given that , The mean score of a cricketer in 10 innings = 60 runs
The mean score of a cricketer in eleventh innings = 62 runs
Required runs = 60 + 11 × 2 = 82 runs
Second method to solve this question with the help of given formula :
Here, T = 60, N = (10 + 1) t = 62 – 60 = 2Correct Option: B
Given that , The mean score of a cricketer in 10 innings = 60 runs
The mean score of a cricketer in eleventh innings = 62 runs
Required runs = 60 + 11 × 2 = 82 runs
Second method to solve this question with the help of given formula :
Here, T = 60, N = (10 + 1) t = 62 – 60 = 2
Required Runs = T + Nt
Required Runs = 60 + 11 × 2 = 82
- The batting average for 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player is
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Let the highest score be n.
∴ Lowest score = n – 172
According to question ,
∴ n + n – 172 = 40 × 50 – 38 × 48
⇒ 2n – 172 = 2000 – 1824 = 176Correct Option: D
Let the highest score be n.
∴ Lowest score = n – 172
According to question ,
∴ n + n – 172 = 40 × 50 – 38 × 48
⇒ 2n – 172 = 2000 – 1824 = 176
⇒ 2n = 176 + 172 = 348
∴ n = 348 ÷ 2 = 174
- The average of six numbers is 20. If one number is removed, the average becomes 15. What is the number removed ?
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Given that ,The average of six numbers = 20
⇒ sum of six numbers = 6 × 20 = 120
The average of 5 numbers = 15
⇒ sum of six numbers = 5 × 5 = 75
∴ Required number = sum of six numbers – sum of five numbersCorrect Option: D
Given that ,The average of six numbers = 20
⇒ sum of six numbers = 6 × 20 = 120
The average of 5 numbers = 15
⇒ sum of six numbers = 5 × 5 = 75
∴ Required number = sum of six numbers – sum of five numbers
Required number = 120 – 75 = 45
