Mechanical and structural analysis miscellaneous


Mechanical and structural analysis miscellaneous

Mechanics and Structural Analysis

  1. For the truss shown in the figure, the force in the member QR is









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    At T,
    MT = RQ × L = P.L
    ∴ RQ = P
    ∴ RQ =QR = P

    Correct Option: C

    At T,
    MT = RQ × L = P.L
    ∴ RQ = P
    ∴ RQ =QR = P


  1. Two people weighing W each are sitting on a plank of length L floating on water at L/4 from either end. Neglecting the weight of the plank, the bending moment at the centre of the plank is









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    At centre,

    BM =
    ×
    L
    ×
    L
    - ω ×
    L
    = 0
    L244

    Correct Option: D

    At centre,

    BM =
    ×
    L
    ×
    L
    - ω ×
    L
    = 0
    L244



  1. A hollow circular shaft has an outer diameter of 100 mm and a wall thickness of 25 mm. The allowable shear stress in the shaft is 125 MPa. The maximum torque the shaft can transmit is









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    α1 = 100 - 2t
    = 100 – 2 × 25 = 50 mm

    τ
    =
    τ
    RJ

    J =
    π
    (1004 - 50)4
    32

    = 9203884.727 mm4
    R = d0/2 = 100/2 = 50 mm
    Tmax =
    τmax × J
    k

    =
    125 × 9203884.727
    = 23 kNm
    50

    Correct Option: C

    α1 = 100 - 2t
    = 100 – 2 × 25 = 50 mm

    τ
    =
    τ
    RJ

    J =
    π
    (1004 - 50)4
    32

    = 9203884.727 mm4
    R = d0/2 = 100/2 = 50 mm
    Tmax =
    τmax × J
    k

    =
    125 × 9203884.727
    = 23 kNm
    50


  1. A thin walled cylindrical pressure vessel having a radius of 0.5 m and wall thickness of 25 mm is subjected to an internal pressure of 700 kPa. The hoop stress developed is









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    Hoop stress: σ =
    pr
    (circular sphere)
    2t

    σ =
    2pr
    (Cylindrical section)
    2t

    =
    700 × 103 × 0.5
    = 14 × 106 = 4 MPa
    25 × 10-3

    Correct Option: A

    Hoop stress: σ =
    pr
    (circular sphere)
    2t

    σ =
    2pr
    (Cylindrical section)
    2t

    =
    700 × 103 × 0.5
    = 14 × 106 = 4 MPa
    25 × 10-3



  1. The stepped cantilever is subjected to movements, M as shown in the figure below. The vertical deflection at the free end (neglecting the self-weight) is









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    B =
    M
    × L ×
    L
    EI2

    =
    ML2
    2EI

    Correct Option: C

    B =
    M
    × L ×
    L
    EI2

    =
    ML2
    2EI