-
A hollow circular shaft has an outer diameter of 100 mm and a wall thickness of 25 mm. The allowable shear stress in the shaft is 125 MPa. The maximum torque the shaft can transmit is
-
- 46 kN m
- 24.5 kN m
- 23 kN m
- 11.5 kN m
Correct Option: C
α1 = 100 - 2t
= 100 – 2 × 25 = 50 mm
| = | ||||
| R | J |
| J = | (1004 - 50)4 | 32 |
= 9203884.727 mm4
R = d0/2 = 100/2 = 50 mm
| Tmax = | k |
| = | = 23 kNm | 50 |
