Mechanical and structural analysis miscellaneous
- For a linear elastic structural system, minimization of potential energy yields
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compatibility conditions
Correct Option: A
compatibility conditions
- The plane frame below is analyzed by neglecting axial deformations. Following statements are made with respect to the analysis
I. Column AB carries axial force only
II. Vertical deflection at the centre of beam BC is 1 mm
With reference to the above statements, which of the following applies?
EI = 81380 kN-m2
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Since there are no horizontal loads, the columns are subjected to axial loads only.
Deflection at centre= 5WL4 = 5 × 10 × 54 = 1 mm 384EI 384.813 Correct Option: A
Since there are no horizontal loads, the columns are subjected to axial loads only.
Deflection at centre= 5WL4 = 5 × 10 × 54 = 1 mm 384EI 384.813
- A propped cantilever of span L is carrying a vertical concentrated load acting at mid span. The plastic moment of the section is Mp. The magnitude of the collapse load is
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Bending moment diagram.
Let P be the load on the prop at collapse, then equating the numerical value of BM at fixed end and centre.MP = Wc × L - Pl 2 p = Wc 2 ∴ MP = Wc L - Wc.l z 3 = Wc.L 6 ∴ Wc = 6Mp L Correct Option: B
Bending moment diagram.
Let P be the load on the prop at collapse, then equating the numerical value of BM at fixed end and centre.MP = Wc × L - Pl 2 p = Wc 2 ∴ MP = Wc L - Wc.l z 3 = Wc.L 6 ∴ Wc = 6Mp L
- The symmetry of stress tensor at a point in the body under equilibrium is obtained from
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moment equilibrium equations
Correct Option: C
moment equilibrium equations
- A simply supported beam AB has the bending moment diagram as shown in the following figure. The beam is possibly under the action of following loads:
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Variation of moment at D = (+m) – (–m) = 2m
Variation of moment at C = (+m) = mCorrect Option: A
Variation of moment at D = (+m) – (–m) = 2m
Variation of moment at C = (+m) = m