Industrial Engineering Miscellaneous
 The standard deviation of the critical path is

View Hint View Answer Discuss in Forum
Variance = t_{p} − t_{O} ^{2} 6 Total variance = 1 ^{2} + 2 ^{2} + 1 ^{2} + 1 ^{2} 3 3 3 3 = 7 9
Standard deviation = √variance
⇒ √7/9 = 0.88Correct Option: C
Variance = t_{p} − t_{O} ^{2} 6 Total variance = 1 ^{2} + 2 ^{2} + 1 ^{2} + 1 ^{2} 3 3 3 3 = 7 9
Standard deviation = √variance
⇒ √7/9 = 0.88
 If an additional constraint X_{1} + X_{2} ≤ 5 is added, the optimal solution is

View Hint View Answer Discuss in Forum
Max z = x_{1} + x_{2}
As feasibly region remains the same solution remains the same (4/3, 4/3).
Hence, the correct option is (b).Correct Option: B
Max z = x_{1} + x_{2}
As feasibly region remains the same solution remains the same (4/3, 4/3).
Hence, the correct option is (b).
 Let Y_{1} and Y_{2} be the decision variables of the dual and v_{1} and v_{2} be the slack variables of the dual of the given linear programming problem. The optimum dual variables are

View Hint View Answer Discuss in Forum
The optimal dual variables are V_{1} & V_{2}.
Correct Option: D
The optimal dual variables are V_{1} & V_{2}.
 The critical path duration of the network (in days) is

View Hint View Answer Discuss in Forum
EST = Earliest start time
LFT = Latest Finish Time
∴ Path along which EST & LFT is equal are called critical path
Critical path duration is 18 days.Correct Option: D
EST = Earliest start time
LFT = Latest Finish Time
∴ Path along which EST & LFT is equal are called critical path
Critical path duration is 18 days.
 A project consists of six activities. The immediate predecessor of each activity and the estimated duration is also provided in the table below:
If all activities other than S take the estimated amount of t i me, t he maxi mum dur at i on (in weeks) of the activity S without delaying the completion of the project is ______.

View Hint View Answer Discuss in Forum
Correct Option: A