Industrial Engineering Miscellaneous

Industrial Engineering Miscellaneous

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Industrial Engineering

Industrial Engineering Miscellaneous
  1. Production flow analysis (PFA) is a method of identifying part families that uses data from








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    Production flow analysis (PFA) is a comprehensive method for material analysis part family formations, design of manufacturing cell & facility layout design. These operation are taken from the Route sheet.

    Correct Option: D

    Production flow analysis (PFA) is a comprehensive method for material analysis part family formations, design of manufacturing cell & facility layout design. These operation are taken from the Route sheet.

  1. On an average 100 customers arrive at a place each hour, and on the average the server can process 120 customers per hour. What is the proportion of time the server is idle?.








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    The proportion of time the server is idle = 1 - ρ

    Correct Option: A

    The proportion of time the server is idle = 1 - ρ

  1. In a single server infinite population queuing model. Arrivals follow a Poisson distribution with mean λ = 4 per hour. The service times are exponential with mean service time equal to 12 minutes. The expected length of the queue will be








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    λ =
    4
    		 , μ =
    1
    6012

    ∴ ρ =
    λ
    		 =
    48
    		 = 0.8
    μ60

    Wq = queue length =
    ρ2
    		 =
    (0.8)2
    		 = 3.2
    (1 – ρ)(1 – 0.8)

    Correct Option: B

    λ =
    4
    		 , μ =
    1
    6012

    ∴ ρ =
    λ
    		 =
    48
    		 = 0.8
    μ60

    Wq = queue length =
    ρ2
    		 =
    (0.8)2
    		 = 3.2
    (1 – ρ)(1 – 0.8)

  1. In a time series forecasting model, the demand for five time periods was 10,13,15,18 and 22. A linear regression fit resulted in an equation F = 6.9 + 2.9 where F is the forecast for period f. The sum of absolute deviations for the five data is








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    F = 6.9 + 2.9 t
    F1 = 6.9 + 2.9 × 1 ⇒ 9.8
    F2 = 6.9 + 2.9 × 2 ⇒ 12.7
    F3 = 6.9 + 2.9 × 3 ⇒ 15.6
    F4 = 6.9 + 2.9 × 4 ⇒ 18.5
    F5 = 6.9 + 2.9 × 5 = 21.4
    D1 = 10 D2 = 13 03 = 15
    D4 = 16 D5 = 22
    SAD = ∑ |ei|
    SAD = |10 − 9.8| + |13 − 12.7| + |15 − 15.6| + |18 − 18.5| + |22 − 21.4 |
    Absolute Deviation = 2.2

    Correct Option: A

    F = 6.9 + 2.9 t
    F1 = 6.9 + 2.9 × 1 ⇒ 9.8
    F2 = 6.9 + 2.9 × 2 ⇒ 12.7
    F3 = 6.9 + 2.9 × 3 ⇒ 15.6
    F4 = 6.9 + 2.9 × 4 ⇒ 18.5
    F5 = 6.9 + 2.9 × 5 = 21.4
    D1 = 10 D2 = 13 03 = 15
    D4 = 16 D5 = 22
    SAD = ∑ |ei|
    SAD = |10 − 9.8| + |13 − 12.7| + |15 − 15.6| + |18 − 18.5| + |22 − 21.4 |
    Absolute Deviation = 2.2

  1. The manufacturing area of a plant is divided into four quadrants. Four machines have to located one in each quadrant. The total number of possible layouts is








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    Way to locate machine at four plans
    4! = 24

    Correct Option: D

    Way to locate machine at four plans
    4! = 24