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If x = a (b – c), y = b (c – a) and z = c (a – b), then x 3 + x 3 + x 3 = a b c
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xyz 3abc - 3xyzabc
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3xyz abc -
xyz abc
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Correct Option: C
= b - c ; | = b - c ; | = b - c | ||||
a | b | c |
Again, b – c + c – a + a – b = 0
∴ | ![]() | ![]() | 3 | + | ![]() | ![]() | 3 | + | ![]() | ![]() | 3 | = ( b - c )3 + ( c - a )3 + ( c - a )3 | |||
a | b | c |
= 3 (b – c) (c – a) (a – b)
Required answer = | ||
abc |