-
If p, q, r are all real numbers, then (p – q)3 + (q – r)3 + (r – p)3 is
equal to
-
- (p – q) (q – r) (r – p)
- 3(p – q) (q – r) (r – p)
- 0
- 1
- (p – q) (q – r) (r – p)
Correct Option: B
Using Rule 21,
Here, p – q + q – r + r – p = 0
∴ (p – q)3 + (q – r)3 + (r – p)3 = 3(p – q)(q – r)(r – p)
[Formula : If a + b + c = 0 , then a3 + b3 + c3 = 3abc]
