If x = k3 – 3k2 and y = 1 – 3k then for what value of

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Using Rule 9
x = k³ – 3k²
y = 1 – 3k
When x = y, then
k³ – 3k² = 1 – 3k
⇒ k³ – 3k² + 3k – 1 = 0
⇒ (k – 1)³ = 0 ⇒ k – 1 = 0
⇒ k = 1