Using Rule 8,p = 99 (Given)∴ p(p2 + 3p + 3) = p3 + 3p2 + 3p = p3 + 3p2 + 3p + 1 - 1= (p + 1)3 - 1 = (99 + 1)3 - 1∴ p(p2 + 3p + 3) = 1003 – 1 = 999999
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