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168. If a + b = 1, find the value of a3 – b3 - ab – (a2 - b2)2
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- –1
- 1
- 0
- 2
- –1
Correct Option: C
a + b = 1 (Given)
Expression = a3 + b3 – ab - (a2 – b2)2
Expression = (a + b)(a2 – ab + b2) – ab - (a2 – b2)2
Expression = 1.(a2 – ab + b2) – ab - (a + b)2(a – b)2
Expression = a2 – ab + b2 – ab - (a2 – 2ab + b2)
Expression = a2 – 2ab + b2 –a2 + 2ab - b2 = 0
