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  1. A builder borrows ₹ 2550 to be paid back with compound interest at the rate of 4% per annum by the end of 2 years in two equal yearly instalments. How much will each instalment be ?
    1. ₹ 1352
    2. ₹ 1377
    3. ₹ 1275
    4. ₹ 1283
Correct Option: A

Here , A = ₹ 2550 , R = 4% per annum , n = 2 years
Let each of the two equal instalments be y .

Present worth =
Instalment
1 +
r
n
100

P1 =
y
1 +
4
1
100
P1 =
y
1 +
1
25
=
y
26
25
or P1 =
25
y
26

Similarly,
P2 =
25
2y =
625
y
26676

P1 + P2 = A
∴ 
25
y +
625
y = 2550
26676

⇒ 
(650 + 625)y
= 2550
676

⇒ 
1275
y = 2550
676

⇒ y = 2550 ×
676
= ₹ 1352
1275

Second Method to solve this question :
Here, P = ₹ 2550, n = 2, r = 4%
Each instalment =
P
100
+
100
2
100 + r100 + r

=
2550
100
+
100
2
100 + 4100 + 4

=
2550
100
+
100
2
104104

Each instalment =
2550
100
1 +
100
104104

Each instalment =
2550
100
204
104104

Each instalment =
2550 × 104 × 104
= ₹ 1352
20400



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