If xx√x = (x√x)x , then x equals

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x^x√x = (x√x)^x
⇒ x^{x.x^1/2} = (x×x^1/2)^{^x}
⇒ x^{x^{1 + (1/2)}} = (x^{1 + (1/2)})^{^x}
x^{x^3/2} = (x^3/2)^{^x} = x ^3x/2

⇒ x^3/2 =	3x	⇒ x^3/2 −	3x	= 0
	2		2

⇒ x		x^1/2 −	3		= 0
			2

⇒ x = 0 or	1	=	3
	x²		2

⇒ x =		3		²	=	9
		2				4

x = 0 given indeterminate value.

∴ x =	9
	4