If x is real, then the minimum value of (x2 – x + 1)

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If x is real, then the minimum value of (x² – x + 1) is

1. 3
  4
2. 0
3. 1
4. 1
  4

Correct Option: A

For expression ax² + bx + c, a > 0, the minimum value is given by

4ac − b²

4a

Here, for x² – x + 1
a = 1, b = –1, c = 1

∴ Minimum value =	4 × 1 × 1 − 1	=	3
	4 × 1		4