Given thata ★ b = 2a + 3b – ab∴ 3 ★ 5 + 5 ★ 3= (2 × 3 + 3 × 5 – 3 × 5) + (5 × 2 + 3 × 3 – 5 × 3)= (6 + 15 – 15) + (10 + 9 – 15)= 6 + 4 = 10
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