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If x varies inversely as (y2 – 1) and is equal to 24 when y = 10, then the value of x when y = 5 is
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- 99
- 12
- 24
- 100
Correct Option: A
x ∝ | |
y2 − 1 |
⇒ x = | |
y2 − 1 |
Where k is a constant.
When y = 10, x = 24, then
∴ 24 = | ⇒ 24 = | ||
y2 − 1 | 99 |
⇒ k = 24 × 99
When y = 5, then
∴ x = | = | = | = 99 | |||
y2 − 1 | 52 − 1 | 24 |