(3a + 1)2 + (b – 1)2 + (2c–3)2 = 0⇒ 3a + 1 = 0⇒ 3a = –1b – 1 = 0⇒ b = 12c – 3 = 0⇒ 2c = 3∴ 3a + b + 2c = –1 + 1 + 3 = 3
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