If (x – 3)2 + (y – 5)2 + (z – 4)2 = 0, then the value

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If (x – 3)² + (y – 5)² + (z – 4)² = 0, then the value of
x² + y² + z² is :
9 25 16

(x – 3)² + (y – 5)² + (z – 4)² = 0
⇒ x – 3 = 0 ⇒ x = 3
y – 5 = 0 ⇒ y = 5
z – 4 = 0 ⇒ z = 4

∴	x²	+	y²	+	z²
	9		25		16

=	9	+	25	+	16
	9		25		16

= 1 + 1 +1 = 3