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If ax2 + bx + c = a (x – p)2 , then the relation among a, b, c would be
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- abc = 1
- b2 = ac
- b2 = 4ac
- 2b = a + c
- abc = 1
Correct Option: C
ax2 + bx + c = a (x – p)2
⇒ ax2 + bx + c = a (x2 – 2px + p2)
⇒ ax2 + bx + c = ax2 – 2apx + ap2
Comparing the corresponding coefficients,
b = – 2ap and c = ap2
⇒ b2 = 4a2p2 and p2 = | |
a |
⇒ p2 = | ; | |
4a2 |
∴ | = | ⇒ b2 = 4ac | ||
4a2 | a |