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  1. If for non-zero, x, x2 – 4x – 1 = 0, the value of x2 +
    1
      is
    x2
    1. 4
    2. 10
    3. 12
    4. 18
Correct Option: D

x2 – 4x – 1 = 0
⇒  x2 –1 = 4x
Dividing by x

x −
1
= 4
x

On squaring both sides,
x −
1
2 = 16
x

⇒  x2 +
1
– 2 = 16
x2

⇒  x2 +
1
= 16 + 2 = 18
x2

Second Method :
Using Rule 5,
Here, x2 – 4x – 1 = 0
⇒  x2 – 1 = 4 x
⇒  x2
1
= 4
x

We know that
x2 +
1
= x −
1
2 + 2
x2x

= 42 + 2 = 18



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