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If for non-zero, x, x2 – 4x – 1 = 0, the value of x2 + 1 is x2
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- 4
- 10
- 12
- 18
Correct Option: D
x2 – 4x – 1 = 0
⇒ x2 –1 = 4x
Dividing by x
x − | = 4 | |
x |
On squaring both sides,
![]() | x − | ![]() | 2 | = 16 | |
x |
⇒ x2 + | – 2 = 16 | |
x2 |
⇒ x2 + | = 16 + 2 = 18 | |
x2 |
Second Method :
Using Rule 5,
Here, x2 – 4x – 1 = 0
⇒ x2 – 1 = 4 x
⇒ x2 – | = 4 | |
x |
We know that
x2 + | = | ![]() | x − | ![]() | 2 | + 2 | ||
x2 | x |
= 42 + 2 = 18