Let a = √6 − √5 , b = √5 −

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Let a = √6 − √5 , b = √5 − 2, c = 2 – √3
Then point out the correct alternative among the four alternatives given below.

1	=	1
a	=	√6 – √5

√6 + √5	= √6 + √5
6 − 5

Similarly,

1	= √5 + 2;	1	= 2 + √3
b		c

∴	1	>	1	>	1	⇒ a < b < c
	a		b		c