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  1. If  
    xy
    = a,
    xz
    = b and
    yz
    = c,
    x + yx + zy + z
    where a, b, c are all non-zero numbers, then x equals to
    1. 2abc
      ab + bc − ac
    2. 2abc
      ab + ac − bc
    3. 2abc
      ac + bc − ab
    4. 2abc
      ab + bc + ac
Correct Option: C

xy
= a ⇒
x + y
=
1
x + yxya

⇒ 
1
+
1
=
1
      ...(i)
yxa

xz
= b     ⇒ 
x + z
=
1
x + zxzb

⇒ 
1
+
1
=
1
      ...(ii)
zxb

Similarly,
1
+
1
=
1
zyc

⇒ 
1
=
1
1
      ...(iii)
ycz

By substitution method
From equations (i) and (iii),
1
1
=
1
1
axcz

⇒ 
1
1
=
1
1
+
1
axcbx

[From equation (ii)]
⇒ 
1
+
1
=
1
1
+
1
xxacb

⇒ 
2
=
bc − ab + ac
xabc

⇒  x =
2abc
bc + ac − ab



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